2q^2-5q-25=0

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Solution for 2q^2-5q-25=0 equation:


Simplifying
2q2 + -5q + -25 = 0

Reorder the terms:
-25 + -5q + 2q2 = 0

Solving
-25 + -5q + 2q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(-5 + -2q)(5 + -1q) = 0

Subproblem 1

Set the factor '(-5 + -2q)' equal to zero and attempt to solve: Simplifying -5 + -2q = 0 Solving -5 + -2q = 0 Move all terms containing q to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -2q = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -2q = 0 + 5 -2q = 0 + 5 Combine like terms: 0 + 5 = 5 -2q = 5 Divide each side by '-2'. q = -2.5 Simplifying q = -2.5

Subproblem 2

Set the factor '(5 + -1q)' equal to zero and attempt to solve: Simplifying 5 + -1q = 0 Solving 5 + -1q = 0 Move all terms containing q to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1q = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1q = 0 + -5 -1q = 0 + -5 Combine like terms: 0 + -5 = -5 -1q = -5 Divide each side by '-1'. q = 5 Simplifying q = 5

Solution

q = {-2.5, 5}

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